1.舞蹈机器人

注:代码有我故意挖的坑,自己查

#include<bits/stdc++.h>
using namespace std;
#define int long long
signed main(){
	int n;
	cin>>n;
	if(n%2==1){
		cout<<(n/2+1)*(n/2+1);
	}
	else{
		cout<<(1+((n+1)/2))*((n+1)/2)/2*4;
	}
	return 0;
}

1 条评论

  • @ 2026-7-10 19:09:51
    #include <bits/stdc++.h>
    using namespace std;
    int main(){
    	int n;
    	cin >> n;
    	int m = n/2+1;
    	if (n%2==0) cout << m*m;
    	else cout << (n+1)*(n+3)/2; 
    }
    • 1